Ask Your Question
1

Quotient of free algebra on 2 generators (x, y) over rational field by a non-homogenous ideal

asked 11 years ago

this post is marked as community wiki

This post is a wiki. Anyone with karma >750 is welcome to improve it.

Hi all,

Here I asked a question in sage but there is an error which I can not solve it:

F.<x,y>=FreeAlgebra(QQ)
I=F*[x*y*x*y-y*x, y*x*y*x-x*y]*F
G.<a,b>=F.quo(I)
G

TypeError: quotient() takes exactly 4 arguments (3 given)


Please help me to find the forth argument should I put.

Actually I want to construct a quotient of infinite dimensional non-commutative free algebra F by a non-homogenous ideal.

Thanks

Preview: (hide)

1 Answer

Sort by » oldest newest most voted
1

answered 11 years ago

this post is marked as community wiki

This post is a wiki. Anyone with karma >750 is welcome to improve it.

It doesn't look like general quotients of free algebras are implemented. See Sage's reference manual for one way to do this: implement a reduce method for your ideal, as in the PowerIdeal class defined in the example. See also the documentation for QuotientRing, although the examples there don't look as helpful.

Preview: (hide)
link

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 11 years ago

Seen: 249 times

Last updated: Oct 09 '13