Ask Your Question
0

Groebner basis

asked 2013-06-20 08:03:04 -0500

Roxana gravatar image

updated 2015-01-14 03:33:31 -0500

FrédéricC gravatar image

hello

I'm trying to compute groebner basis for I=( x^2+y+z-1,x+y^2+z-1,x+y+z^2-1) in sage, but why the groebner basis of this ideal is same as ideal? thank you

edit retag flag offensive close merge delete

2 answers

Sort by » oldest newest most voted
1

answered 2013-06-20 14:41:06 -0500

The three polynomials used to describe the particular ideal in your example are a Groebner basis for it.

sage: R.<x,y,z> = PolynomialRing(QQ,3)
sage: I = Ideal([x^2+y+z-1,x+y^2+z-1,x+y+z^2-1])
sage: B = I.groebner_basis(); B
[x^2 + y + z - 1, y^2 + x + z - 1, z^2 + x + y - 1]

However, the ideal and its Groebner basis are not the same. Check their type and their parent.

sage: type(I)
<class 'sage.rings.polynomial.multi_polynomial_ideal.MPolynomialIdeal'>
sage: I.parent()
Monoid of ideals of Multivariate Polynomial Ring in x, y, z over Rational Field
sage: type(B)
<class 'sage.rings.polynomial.multi_polynomial_sequence.PolynomialSequence_generic'>
sage: B.parent()
Category of sequences in Multivariate Polynomial Ring in x, y, z over Rational Field

Also, if you check the documentation for groebner_basis, you will find examples of families of polynomials who are not a Groebner basis for the ideal they generate.

sage: I.groebner_basis?
edit flag offensive delete link more
0

answered 2013-06-23 14:00:35 -0500

Volker Braun gravatar image

Also note that the Groebner basis depends on the monomial ordering:

sage: R.<x,y,z> = PolynomialRing(QQ, 3, order='lex')
sage: I = Ideal([x^2+y+z-1,x+y^2+z-1,x+y+z^2-1])
sage: I.groebner_basis()
[x + y + z^2 - 1, y^2 - y - z^2 + z, y*z^2 + 1/2*z^4 - 1/2*z^2, z^6 - 4*z^4 + 4*z^3 - z^2]

vs.

sage: S.<x,y,z> = PolynomialRing(QQ, 3, order='deglex')
sage: J = Ideal([x^2+y+z-1,x+y^2+z-1,x+y+z^2-1])
sage: J.groebner_basis()
[x^2 + y + z - 1, y^2 + x + z - 1, z^2 + x + y - 1]
edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

Stats

Asked: 2013-06-20 08:03:04 -0500

Seen: 679 times

Last updated: Jun 23 '13