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Can I define an n-dimensional matrix?

asked 2013-06-15 08:52:18 -0500

mudd1 gravatar image

updated 2013-06-15 09:09:28 -0500

I'm sure this is a basic question that has been asked before but I'm too stupid to find it.

What I'd like to do is something like this

k=var('n')
assume(n, 'integer')
assume(n>0)
VS = MatrixSpace(SR, n, 1)

to get the space of all n×1 matrices, i.e. column vectors. Is it at all possible to define a generalized n-dimensional vector or n×n matrix? Or am I just taking the completely wrong approach here?

Edit: Forgot to mention that the error I get is

ValueError: cannot convert n to int
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answered 2013-06-16 01:41:07 -0500

tmonteil gravatar image

updated 2013-06-16 01:51:19 -0500

There is no way to define a MatrixSpace without fixing the number of columns and rows. You can see this by looking into the code:

sage: MatrixSpace??
    [...]
    def __init__(self,...
    [...]
        nrows = int(nrows)
        ncols = int(ncols)

Hence, Sage can not accept a symbolic variable n as the number of columns/rows.

A question remains : what do you want to ask to Sage about such a general matrix space where entries are not determined ? There maybe a workaround for a precise question.

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Comments

Well, generally what I'd like to do is some linear algebra without specifying the number of dimensions but just getting results that are true for arbitrary *n*. Guess that was to general an answer? I figured out my current problems by hand but it'd still be nice to have a software that can do such things.

mudd1 gravatar imagemudd1 ( 2013-06-16 12:43:51 -0500 )edit

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Asked: 2013-06-15 08:52:18 -0500

Seen: 135 times

Last updated: Jun 16 '13