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How to use algorithm='mathematica free' to calculate definite integral?
 
  
 
  
 
 
 
 
 
 
    
        
        asked 11 years ago  
 
 IvanG gravatar image  
 
 
 
 
    
        
        updated 2 years ago  
 
 tmonteil gravatar image  
 
 
 
 
 
Is it possible to use algorithm='mathematica free' to calculate definite integral ?
 
integrate(x^2,x,algorithm='mathematica_free')
 
Output:
 
1/3*x^3
 
and 
 
integrate(x^2,x,0,1,algorithm='mathematica_free')
 
Output:
 
1/3*x^3
 
but I want 1/3
 
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Comments
1
Looks like mathematica_free only calculates indefinite integrals.  http://integrals.wolfram.com    ... so Sage would need to apply the limits after receiving the indefinite result.  As a work-around you could define a function that passes the integrand to mathematica_free and then performs the difference after applying the variable limits.
rickhg12hs gravatar imagerickhg12hs (
    
        11 years ago
    )
1
If Sage wanted to calculate the definite integral as described in my previous comment,a simple change to sage/symbolic/integration/external.py could accomplish this.  One wonders what would happen with wacky input/output though.
rickhg12hs gravatar imagerickhg12hs (
    
        11 years ago
    )
Thanks for comments!
IvanG gravatar imageIvanG (
    
        11 years ago
    )
2
I've opened http://trac.sagemath.org/sage_trac/ticket/14764
kcrisman gravatar imagekcrisman (
    
        11 years ago
    )
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        answered 11 years ago  
 
 IvanG gravatar image  
 
 
 
 
 
Thanks for comments!
 
x=var('x')
f = lambda x : x^2
def defintegral_viaMathFree(f,x,a,b):
F(x)=integrate(f(x),x,algorithm='mathematica_free')
return F(b)-F(a)
 
And 
 
defintegral_viaMathFree(f,x,0,1)
 
output: 1/3
 
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        Asked:  11 years ago  
 
 
        Seen: 949 times 
 

        Last updated: Jun 18 '13 
 
 
 
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