Consider the function f(x)=x^2 if x is non-negative; f(x)=3-x^2 if x is negative.
Now,does f(x) have a point of inflection at x=0. It is clear that f(x) is convex for x<0 and concave for x>0.
The definition of an inflection point only makes sense on a continuous and differentiable curve.
Asked: 2013-05-13 12:33:02 +0200
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Last updated: May 13 '13
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