1 | initial version |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 1), (t, -2, 2),aspect_ratio=1)
```

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for t sufficiently large anyway.

2 | No.2 Revision |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 1), (t, -2, 2),aspect_ratio=1)
```

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for ~~t ~~$t$ sufficiently large ~~anyway. ~~anyway.

3 | No.3 Revision |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 1), (t, -2,
```~~2),aspect_ratio=1)
~~2))

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ sufficiently large anyway.

4 | No.4 Revision |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma,
```~~-1, ~~0, 1), (t, -2, 2))

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ sufficiently large anyway.

If you want to symmetric version you may try

```
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
```

5 | No.5 Revision |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
```

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ sufficiently large anyway.

If you want ~~to ~~the symmetric version you may try

```
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
```

6 | No.6 Revision |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
```

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for ~~$t$ ~~$\lvert t \rvert$ sufficiently large anyway.

If you want the symmetric version you may try

```
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
```

7 | No.7 Revision |

Maybe something like

```
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t,
```~~-2, 2))
~~-100, 100),aspect_ratio=1/99)

will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $\lvert t \rvert$ sufficiently large anyway.

If you want the symmetric version you may try

`region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, `~~-2, 2))+region_plot((sigma)-c/log(2+abs(t))<= ~~-100, 100),aspect_ratio=1/99)+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, ~~-2, 2))
~~-100, 100),aspect_ratio=1/99)

Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.