1 | initial version |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 1), (t, -2, 2),aspect_ratio=1)
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for t sufficiently large anyway.
2 | No.2 Revision |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 1), (t, -2, 2),aspect_ratio=1)
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for t $t$ sufficiently large anyway. anyway.
3 | No.3 Revision |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 1), (t, -2, 2),aspect_ratio=1)
2))
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ sufficiently large anyway.
4 | No.4 Revision |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, -1, 0, 1), (t, -2, 2))
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ sufficiently large anyway.
If you want to symmetric version you may try
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
5 | No.5 Revision |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ sufficiently large anyway.
If you want to the symmetric version you may try
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
6 | No.6 Revision |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $t$ $\lvert t \rvert$ sufficiently large anyway.
If you want the symmetric version you may try
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
7 | No.7 Revision |
Maybe something like
var('sigma,t')
c=0.3
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
-100, 100),aspect_ratio=1/99)
will do the trick. Notice that I have changed the argument of the log a bit to make it non-negative. The form of the Hadamard-dVP region you have stated is only nontrivial for $\lvert t \rvert$ sufficiently large anyway.
If you want the symmetric version you may try
region_plot((1-sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))+region_plot((sigma)-c/log(2+abs(t))<= -100, 100),aspect_ratio=1/99)+region_plot((sigma)-c/log(2+abs(t))<= 0, (sigma, 0, 1), (t, -2, 2))
-100, 100),aspect_ratio=1/99)