1 | initial version |

From the documentation of `roots`

:

Return roots of

`self`

that can be found exactly, possibly with multiplicities. Not all roots are guaranteed to be found.

Warning:This isnota numerical solver

and

`ring`

- a ring (default None): if not None, convert self to a polynomial over ring and find roots over ring

The latter explains why you get the error in the title: the expression is not a polynomial, so the conversion fails.

The expression itself is only defined as a real number if `y`

is between 0 and 10 (due to the $\sqrt{y(10-y}$), so:

```
sage: var('y')
sage: f = sqrt(10*y*(10-y))+sqrt(1000)*acos(sqrt(y/10))-15*sqrt(2*6.673*10^(-11)*50000000000)
sage: f.find_root(0,10)
5.5672155196677675
sage: find_root(f,0,10)
5.5672155196677675
```

By plotting `f`

you see that it's the only root.

In general there is no magic method to find an interval where a root may live. It is however always a good idea to check the domain of definition first.

2 | No.2 Revision |

From the documentation of `roots`

:

Return roots of

`self`

that can be found exactly, possibly with multiplicities. Not all roots are guaranteed to be found.

Warning:This isnota numerical solver

and

`ring`

- a ring (default None): if not None, convert self to a polynomial over ring and find roots over ring

The latter explains why you get the error in the title: the expression is not a polynomial, so the conversion fails.

The expression itself is only defined as a real number if `y`

is between 0 and 10 (due to the ~~$\sqrt{y(10-y}$), ~~$\sqrt{y(10-y)}$), so:

```
sage: var('y')
sage: f = sqrt(10*y*(10-y))+sqrt(1000)*acos(sqrt(y/10))-15*sqrt(2*6.673*10^(-11)*50000000000)
sage: f.find_root(0,10)
5.5672155196677675
sage: find_root(f,0,10)
5.5672155196677675
```

By plotting `f`

you see that it's the only root.

In general there is no magic method to find an interval where a root may live. It is however always a good idea to check the domain of definition first.

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