1 | initial version |

The problem comes from the fact that `funkce`

is a symbolic expression and so it is `f`

. Since `f`

is not a symbolic callable function, you can not use the notation `f(x)`

. You have to replace `x`

by the corresponding value, writing either `f.subs(x=value)`

or `f(x=value)`

. So a simple solution is to replace

```
ys = [f(x) for x in xs]
```

and

```
yz = [f(t) for t in xz]
```

by

```
ys = [f(x=x) for x in xs]
```

and

```
yz = [f(x=t) for t in xz]
```

Hope this helps.

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