1 | initial version |

I fiddled around and got it to work by changing the `legend_label`

:

```
var("x_1","x_2")
eq1=solve(3*x_1+4*x_2==14,x_2)
eq2=solve(5*x_1+6*x_2==-8,x_2)
eq3=solve(4*x_1-7*x_2==18,x_2)
eq4=solve(2*x_1-3*x_2==-8,x_2)
b=10
p=plot([eq1[0].rhs(),eq2[0].rhs(),eq3[0].rhs(),eq4[0].rhs()], (x_1, 0,b),color=["#c72b91","#2b37c7", "#cb7b2b","#2bcb4b"],axes_labels=["$x_1$","$x_2$"],legend_label=[r"$%s$"%latex(eq1[0].rhs()),r"$%s$"%latex(eq2[0].rhs()),r"$%s$"%latex(eq3[0].rhs()),r"$%s$"%latex(eq4[0].rhs())])
show(p)
```

This is the result:

Since there are several equations in the legend, I use a list. Looking at that part of the code,
`r"$%s$"%latex(eq1[0].rhs())`

accomplishes the task by first getting the latex code for `eq1[0].rhs()`

with `latex(eq1[0].rhs())`

followed by inserting that in for the string r"$%s$. The `r`

is for a raw string and since its a formula, LaTeX needs it between dollar signs.

2 | No.2 Revision |

I fiddled around and got it to work by changing the `legend_label`

:

```
var("x_1","x_2")
eq1=solve(3*x_1+4*x_2==14,x_2)
eq2=solve(5*x_1+6*x_2==-8,x_2)
eq3=solve(4*x_1-7*x_2==18,x_2)
eq4=solve(2*x_1-3*x_2==-8,x_2)
b=10
p=plot([eq1[0].rhs(),eq2[0].rhs(),eq3[0].rhs(),eq4[0].rhs()], (x_1, 0,b),color=["#c72b91","#2b37c7", "#cb7b2b","#2bcb4b"],axes_labels=["$x_1$","$x_2$"],legend_label=[r"$%s$"%latex(eq1[0].rhs()),r"$%s$"%latex(eq2[0].rhs()),r"$%s$"%latex(eq3[0].rhs()),r"$%s$"%latex(eq4[0].rhs())])
show(p)
```

This is the result:

Since there are several equations in the legend, I use a list. Looking at that part of the code,
`r"$%s$"%latex(eq1[0].rhs())`

accomplishes the task by first getting the latex code for `eq1[0].rhs()`

with `latex(eq1[0].rhs())`

followed by inserting that in for the string r"$%s$. The `r`

is for a raw string and since its a formula, LaTeX needs it between dollar signs.

It seems a bit awkward, maybe others have a more efficient way.

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