1 | initial version |

Thanks for the answer. I see why Sagemath gives one answer and Mathematica gives 3. I tried to solve this using "fricas", it gave me the 3 roots.

Though I still think when the initial conditions are invoked, desolve solves it wrong, since the denominator is zero.

Is there a way to get the (in this example--) cube roots from desolve result? or perhaps I should open up another thread for this.

2 | No.2 Revision |

Thanks for the answer. I see why Sagemath gives one answer and Mathematica gives 3. I tried to solve this using "fricas", it gave me the 3 roots.

Though I still think when the initial conditions are invoked, desolve solves it wrong, since the denominator is zero. The initial condition can be satisfied by one of the cube roots.

Is there a way to get the (in this example--) cube roots from desolve result? or perhaps I should open up another thread for ~~this. ~~this.

3 | No.3 Revision |

Thanks for the answer. I see why Sagemath gives one answer and Mathematica gives 3. I tried to solve this using "fricas", it gave me the 3 roots.

Though I still think when the initial conditions are invoked, desolve solves it wrong, since the denominator is zero. The initial condition can be satisfied by one of the cube ~~roots. ~~roots (checked with Mathematica)

Is there a way to get the (in this example--) cube roots from desolve result? or perhaps I should open up another thread for this.

4 | No.4 Revision |

Though I still think when the initial conditions are invoked, desolve solves it ~~wrong, ~~wrong with maxima, since the denominator is zero. The initial condition can be satisfied by one of the cube roots (checked with Mathematica)

Is there a way to get the (in this example--) cube roots from desolve result? or perhaps I should open up another thread for this.

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