1 | initial version |

Simply generate a random nine-digits integer, ten insert a one at the "last" place. Here is a possibility using the random package:

```
sage: import random
sage: a = random.choice(range(10^8, 10^9)) * 10 + 1
sage: a
9768350121
```

Or we offer directly the corresponding range to the `random.choice`

method:

```
sage: random.choice(range(10^9 + 1, 10^10, 10))
8455325531
```

Here, `range(10^9 + 1, 10^10, 10)`

is a range-object, which "consumed" points to the integers taken from $10^9+1$ with step $10$ going up to maximally (and excluding) $10^{10}$. Then `random.choice`

called with this range instance picks one random element of the corresponding list.

2 | No.2 Revision |

~~Simply ~~We can simply generate a random nine-digits integer, ~~ten ~~then insert a one at the "last" place. Here is a possibility using the random package:

```
sage: import random
sage: a = random.choice(range(10^8, 10^9)) * 10 + 1
sage: a
9768350121
```

Or we offer directly the corresponding range to the `random.choice`

method:

```
sage: random.choice(range(10^9 + 1, 10^10, 10))
8455325531
```

Here, `range(10^9 + 1, 10^10, 10)`

is a range-object, which "consumed" points to the integers taken from $10^9+1$ with step $10$ going up to maximally (and excluding) $10^{10}$. Then `random.choice`

called with this range instance picks one random element of the corresponding ~~list. ~~list.

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