1 | initial version |
Simply generate a random nine-digits integer, ten insert a one at the "last" place. Here is a possibility using the random package:
sage: import random
sage: a = random.choice(range(10^8, 10^9)) * 10 + 1
sage: a
9768350121
Or we offer directly the corresponding range to the random.choice
method:
sage: random.choice(range(10^9 + 1, 10^10, 10))
8455325531
Here, range(10^9 + 1, 10^10, 10)
is a range-object, which "consumed" points to the integers taken from $10^9+1$ with step $10$ going up to maximally (and excluding) $10^{10}$. Then random.choice
called with this range instance picks one random element of the corresponding list.
2 | No.2 Revision |
Simply We can simply generate a random nine-digits integer, ten then insert a one at the "last" place. Here is a possibility using the random package:
sage: import random
sage: a = random.choice(range(10^8, 10^9)) * 10 + 1
sage: a
9768350121
Or we offer directly the corresponding range to the random.choice
method:
sage: random.choice(range(10^9 + 1, 10^10, 10))
8455325531
Here, range(10^9 + 1, 10^10, 10)
is a range-object, which "consumed" points to the integers taken from $10^9+1$ with step $10$ going up to maximally (and excluding) $10^{10}$. Then random.choice
called with this range instance picks one random element of the corresponding list. list.