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Hello, @GA316. There are two ways to do this, depending on whether you want to do it manually or automatically.

To remove rows manually, you just need to use the delete_rows method: Suppose you have a matrix A such that its 3rd, 5th and 6th rows are exactly the same as the first row, so they should be removed. Just execute:

A.delete_rows([3, 5, 6])

If you want to do it automatically, the following piece of code can help you:

def remove_repeated_rows(A):
    nr = A.nrows()# number of rows
    eliminate = []# this will store the numbers of the rows to eliminate

    for i in range (nr-1):# check all rows, except the last one
        for j in range(i+1, nr):# compare to the rows bellow row i
            if A[i] == A[j]:    eliminate.append(j)# if row j equals row i, list j to eliminate

    return A.delete_rows(eliminate)# eliminate the listed rows and return the resulting submatrix

I hope this helps!

Hello, @GA316. There are two ways to do this, depending on whether you want to do it manually or automatically.

To remove rows manually, you just need to use the delete_rows method: Suppose you have a matrix A such that its 3rd, 5th and 6th rows are exactly the same as the first row, so they should be removed. Just execute:

A.delete_rows([3, 5, 6])

If you want to do it automatically, the following piece of code can help you:

def remove_repeated_rows(A):
    nr = A.nrows()# number of rows
    eliminate = []# this will store the numbers of the rows to eliminate

    for i in range (nr-1):# check all rows, except the last one
        for j in range(i+1, nr):# compare to the rows bellow below row i
            if A[i] == A[j]:    eliminate.append(j)# if row j equals row i, list j to eliminate

    return A.delete_rows(eliminate)# eliminate the listed rows and return the resulting submatrix

I hope this helps!