1 | initial version |

Depending on the real need, the one or the other of the following code snippets may be preferable.

(1) Arrange the range.

```
R = [0..2] + [20] + [5..8]
for r in R:
print r
```

(2) Define a function that does the right thing for the right `k`

:

```
def f(k):
if k == 3: print 20
elif k == 4: pass
else: print k
for k in [0..8]:
f(k)
```

(3) Do the same as above without function.

```
for k in [0..8]:
if k == 4: continue
elif k == 3: print 20
else: print k
```

(4) If in the real application we have no good control of the position, after that we skip, we can use a flag, `skipNext`

say...

def myCondition(k): if k == 3: return True return False

nextSkip = False for k in range(9): oldSkip = nextSkip nextSkip = myCondition(k) if oldSkip: continue if nextSkip: print 20 else: print k

You see how hard is to guess the "needed solution". The question is a pure python question, consider reviewing data structures in python and logical ramification possibilites.

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