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Depending on the real need, the one or the other of the following code snippets may be preferable.

(1) Arrange the range.

R = [0..2] + [20] + [5..8]
for r in R:
    print r

(2) Define a function that does the right thing for the right k:

def f(k):
    if k == 3:    print 20
    elif k == 4:    pass
    else:    print k

for k in [0..8]:
    f(k)

(3) Do the same as above without function.

for k in [0..8]:
    if k == 4:    continue
    elif k == 3:    print 20
    else:    print k

(4) If in the real application we have no good control of the position, after that we skip, we can use a flag, skipNext say...

def myCondition(k): if k == 3: return True return False

nextSkip = False for k in range(9): oldSkip = nextSkip nextSkip = myCondition(k) if oldSkip: continue if nextSkip: print 20 else: print k

You see how hard is to guess the "needed solution". The question is a pure python question, consider reviewing data structures in python and logical ramification possibilites.