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# Revision history [back]

Sure, you can do it that way. You can omit the lines

u0 = function ('u0')(w, tau_t0, s_t0)
u1 = function ('u1')(w, tau_t1, s_t1)
u2 = function ('u2') (n, w, tau_t0, r, s_t0, s_t1)


because the subsequent lines just redefine u0,u1,u2 using Sage syntax for function definition.

You could also replace the functions u0,u1,u2 by their values (since you only use the values):

var('w,tau_t0,tau_t1,s_t0,s_t1,r,n')

u0 = w*(1-tau_t0) - s_t0
u1 = w*(1-tau_t1) - s_t1
u2 = (1+n)^2 * w * tau_t0 + (1+n) * w * tau_t0 + (1+r)^2 * s_t0 + (1+r) * s_t1

a = diff(u0, s_t0)
b = diff(u1, s_t0)
c = diff(u2, s_t0)

U = a + b + c
U


Sure, you can do it that way. You can omit the lines

u0 = function ('u0')(w, tau_t0, s_t0)
u1 = function ('u1')(w, tau_t1, s_t1)
u2 = function ('u2') (n, w, tau_t0, r, s_t0, s_t1)


because the subsequent lines just redefine u0,u1,u2 using Sage syntax for function definition.

You could also replace the functions u0,u1,u2 by their values (since you only use the values):

var('w,tau_t0,tau_t1,s_t0,s_t1,r,n')

u0 = w*(1-tau_t0) - s_t0
u1 = w*(1-tau_t1) - s_t1
u2 = (1+n)^2 * w * tau_t0 + (1+n) * w * tau_t0 + (1+r)^2 * s_t0 + (1+r) * s_t1

a = diff(u0, s_t0)
b = diff(u1, s_t0)
c = diff(u2, s_t0)

U = a + b + c
U


Since partial differentiation is linear, you can also define U in terms of u0,u1,u2 in one step:

U = diff(u0+u1+u2, s_t0)