Revision history [back]
 | 1 | initial version |
What is wrong is the following argument ?
The degree of $phi-phi'$ is d (4 in your example), which is smaller than the degree of h (which is 8 in your example). Hence, $phi-phi' = 0 mod h$ is equivelent to $phi-phi' = 0$. Hence $phi = 0'$ is the only solution to the equation.
| | 2 | No.2 Revision |
What is wrong is the following argument ?
The degree of $phi-phi'$ is d (4 in your example), d, which is smaller than the degree of h (which is 8 in your example). Hence, $phi-phi' = 0 mod h$ is equivelent to $phi-phi' = 0$. Hence $phi = 0'$ is the only solution to the equation.since $d<h$. hence,="" $phi-phi'="0" mod="" h$="" is="" equivalent="" to="" $phi-phi'="0$." hence="" $phi="0'$" is="" the="" only="" solution="" to="" the="" equation.<="" p="">
| | 3 | No.3 Revision |
What is wrong is the following argument ?
The degree of $phi-phi'$ is d, which is smaller than the degree of h since $d<h$. hence,="" $phi-phi'="0" mod="" h$="" is="" equivalent="" to="" $phi-phi'="0$." hence="" $phi="0'$" is="" the="" only="" solution="" to="" the="" equation.<="" p="">
| | 4 | No.4 Revision |
What is wrong is the following argument ?
The degree of $phi-phi'$ $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$. hence,="" $phi-phi'="0" $\phi-\phi'="0" mod="" h$="" is="" equivalent="" to="" $phi-phi'="0$." $\phi-\phi'="0$." hence="" $phi="0'$" $\phi="0'$" is="" the="" only="" solution="" to="" the="" equation.<="" p="">
| | 5 | No.5 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$. hence,="" $\phi-\phi'="0" mod="" h$="" is="" equivalent="" to="" $\phi-\phi'="0$." hence="" $\phi="0'$" is="" the="" only="" solution="" to="" the="" equation.<="" p="">
| | 6 | No.6 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$. $d<h$ .="" hence,="" $\phi-\phi'="0" mod="" h$="" is="" equivalent="" to="" $\phi-\phi'="0$." hence="" $\phi="0'$" is="" the="" only="" solution="" to="" the="" equation.<="" p="">
| | 7 | No.7 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$ .="" hence,="" $\phi-\phi'="0" mod="" h$="" is="" equivalent="" to="" $\phi-\phi'="0$." hence="" $\phi="0'$" is="" the="" only="" solution="" to="" the="" equation.<="" .<="" p="">
Hence, $\phi-\phi' = 0 \mod h$ is equivalent to $\phi-\phi' = 0$. Hence $\phi = 0'$ is the only solution to the equation.
| | 8 | No.8 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$ .<="" p="">
Hence, $\phi-\phi' = 0 \mod h$ is equivalent to $\phi-\phi' = 0$. Hence $\phi = 0'$ 0$ is the only solution to the equation.
| | 9 | No.9 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$ .<="" $d<h$.< p="">
Hence, $\phi-\phi' = 0 \mod h$ is equivalent to $\phi-\phi' = 0$. Hence $\phi = 0$ is the only solution to the equation.
| | 10 | No.10 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$.< $d<h$< p="">
Hence, $\phi-\phi' = 0 \mod h$ is equivalent to $\phi-\phi' = 0$. Hence $\phi = 0$ is the only solution to the equation.
| | 11 | No.11 Revision |
What is wrong is the following argument ?
The degree of $\phi-\phi'$ is d, which is smaller than the degree of h since $d<h$< $d<h$ <="" p="">
Hence, $\phi-\phi' = 0 \mod h$ is equivalent to $\phi-\phi' = 0$. Hence $\phi = 0$ is the only solution to the equation.
