1 | initial version |

Technically, in matplotlib the ticks are an attribute of the shown object, not the object itself. There is something called an `Axes`

object to which ticks belong. That said, you can pass the ticks this way:

u = var('u')
array = [vector([u, cos(i*u)]) for i in range(0, 3)]
P = [parametric_plot(array[i], (u, 0, 2*pi),ticks=[[0,i],[0,i]]) for i in range(len(array))]
g = graphics_array(P)
g

but you will see this doesn't give what you want either; only the last one has the custom ticks. The problem is that we haven't found a good way to resolve https://trac.sagemath.org/ticket/10466 or https://trac.sagemath.org/ticket/10657

2 | No.2 Revision |

Technically, in matplotlib the ticks are an attribute of the shown object, not the object itself. There is something called an `Axes`

object to which ticks belong. That said, you can pass the ticks this way:

```
u = var('u')
array = [vector([u,
```~~cos(i~~*u)]) **cos(i*u)]) for i in range(0, 3)]
P = [parametric_plot(array[i], (u, 0, *~~2~~pi),ticks=[[0,i],[0,i]]) 2*pi),ticks=[[0,i],[0,i]]) for i in range(len(array))]
g = graphics_array(P)
~~g~~g

but you will see this doesn't give what you want either; only the last one has the custom ticks. The problem is that we haven't found a good way to resolve https://trac.sagemath.org/ticket/10466 or https://trac.sagemath.org/ticket/10657