# Revision history [back]

In the documentation for solve there is an option which often helps solve these kinds of equations.

F = 2*(1-sin(x)) == 1-cos(x)
solve(F,x,to_poly_solve=True)


You should get

[x == pi + 2*pi*z38, x == 2*pi*z40 + arctan(4/3)]


where the z38 means an integer parameter.

In the documentation for solve there is an option which often helps solve these kinds of equations.

F = 2*(1-sin(x)) == 1-cos(x)
solve(F,x,to_poly_solve=True)


You should getget something like

[x == pi + 2*pi*z38, x == 2*pi*z40 + arctan(4/3)]


where the z38 means an integer parameter.