1 | initial version |

In the documentation for `solve`

there is an option which often helps solve these kinds of equations.

```
F = 2*(1-sin(x)) == 1-cos(x)
solve(F,x,to_poly_solve=True)
```

You should get

```
[x == pi + 2*pi*z38, x == 2*pi*z40 + arctan(4/3)]
```

where the `z38`

means an integer parameter.

2 | No.2 Revision |

In the documentation for `solve`

there is an option which often helps solve these kinds of equations.

```
F = 2*(1-sin(x)) == 1-cos(x)
solve(F,x,to_poly_solve=True)
```

You should ~~get~~get something like

```
[x == pi + 2*pi*z38, x == 2*pi*z40 + arctan(4/3)]
```

where the `z38`

means an integer parameter.

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