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 | 1 | initial version |
In the documentation for solve there is an option which often helps solve these kinds of equations.
F = 2*(1-sin(x)) == 1-cos(x)
solve(F,x,to_poly_solve=True)
You should get
[x == pi + 2*pi*z38, x == 2*pi*z40 + arctan(4/3)]
where the z38 means an integer parameter.
| | 2 | No.2 Revision |
In the documentation for solve there is an option which often helps solve these kinds of equations.
F = 2*(1-sin(x)) == 1-cos(x)
solve(F,x,to_poly_solve=True)
You should getget something like
[x == pi + 2*pi*z38, x == 2*pi*z40 + arctan(4/3)]
where the z38 means an integer parameter.
