1 | initial version |
This does not appear to be implemented in sage. The code below may be an option to get that functionality
def all_paths(G,a,b):
paths = G.all_paths( a, b ) # get all paths without edge multiplicity
multi_paths=[]
for p in paths: # we will traverse each path replacing each edge by a list of (multi) edges
multi_edges=[]
for i,u in enumerate(p):
if i < len(p)-1:
v = p[i+1]
edges = A.edge_boundary([u], [v] )
multi_edges.append(edges)
multi_paths.append( multi_edges ) # each sequence of (multi) edges will be a source of multiple paths
paths = []
for multi_path in multi_paths:
paths.extend(CartesianProduct(*multi_path)) # we extract all possible paths from a given multi path
return paths
Then you can use
paths=all_paths(A,1,3)
print len(paths)
for p in paths:
print p
2 | No.2 Revision |
This does not appear to be implemented in sage. The code below may be an option to get that functionality
def all_paths(G,a,b):
paths old_paths = G.all_paths( a, b ) # get all paths without edge multiplicity
multi_paths=[]
new_paths=[]
for p in paths: old_paths: # we will traverse each path replacing each edge by a list of (multi) edges
multi_edges=[]
multi_path=[]
for i,u in enumerate(p):
if i < len(p)-1:
v = p[i+1]
edges = A.edge_boundary([u], [v] )
multi_edges.append(edges)
multi_paths.append( multi_edges ) multi_path.append(edges)
new_paths.extend( CartesianProduct(*multi_path )) # each sequence of (multi) edges will be a source of multiple paths
paths = []
for multi_path in multi_paths:
paths.extend(CartesianProduct(*multi_path)) # we extract all possible paths from a given multi path
paths
return paths
new_paths
Then you can use
paths=all_paths(A,1,3)
print len(paths)
for p in paths:
print p
3 | No.3 Revision |
This does not appear to be implemented in sage. The code below may be an option to get that functionality
def all_paths(G,a,b):
old_paths = G.all_paths( a, b ) # get all paths without edge multiplicity
new_paths=[]
for p in old_paths: # we will traverse each path replacing each edge by a list of (multi) edges
multi_path=[]
for i,u in enumerate(p):
if i < len(p)-1:
v = p[i+1]
edges = A.edge_boundary([u], G.edge_boundary([u], [v] )
multi_path.append(edges)
new_paths.extend( CartesianProduct(*multi_path )) # each sequence of (multi) edges will be a source of multiple paths
return new_paths
Then you can use
paths=all_paths(A,1,3)
print len(paths)
for p in paths:
print p