# Revision history [back]

As you can see eq2 is a list containing a single element:

sage: eq2
[b == -a + d]


To get it, just type

sage: eq2[0]
b == -a + d


Now this equality has two sides. You can get its left hand side, and right hand side as folows:

sage: eq2[0].left_hand_side()
b
sage: eq2[0].right_hand_side()
-a + d


or simply:

sage: eq2[0].lhs()
b
sage: eq2[0].rhs()
-a + d


As you can see eq2 is a list containing a single element:

sage: eq2
[b == -a + d]


To get it, just type

sage: eq2[0]
b == -a + d


Now this equality has two sides. You can get its left hand side, and right hand side as folows:

sage: eq2[0].left_hand_side()
b
sage: eq2[0].right_hand_side()
-a + d


or simply:

sage: eq2[0].lhs()
b
sage: eq2[0].rhs()
-a + d


So, i guess what you are looking for is:

sage: eq3=c/eq2[0].rhs()
sage: eq3
-c/(a - d)