Ask Your Question

Revision history [back]

As explained by @Luca, it is not a good idea to have indices as a substring of the name of your lists, but as indices (list[i] makes more sense than list_i).

Lists indices go from 0 to length-1, so if a is big (or if the set of indices is sparse), you should better use a dictionary instead. For example, assume that the i^th element (more precisely the element whose key is i) of your dictionary is the list [i,i^2], you can write:

sage: a = 10
sage: b = 20

sage: dict_number = {}
sage: for i in srange(a, b+1, 1):
....:     dict_number[i] = [i, i^2]

Then you can call the 13^th element of your dictionary:

sage: dict_number[13]
[13, 169]

Note that the keys of your dictionary can be more than just numbers, for example they can be strings:

sage: dict_number['plop'] = [12,13]
sage: dict_number['plop']          
[12, 13]

You can read more about python dictionaries here.

As explained by @Luca, it is not a good idea to have indices as a substring of the name of your lists, but as indices (list[i]indices: list_number[i] makes more sense than list_i).list_number_i.

Lists indices go from 0 to length-1, so if a is big (or if the set of indices is sparse), you should better can use a dictionary instead. For example, assume that the i^th element (more precisely the element whose key is i) of your dictionary is the list [i,i^2], you can write:

sage: a = 10
sage: b = 20

sage: dict_number = {}
sage: for i in srange(a, b+1, 1):
....:     dict_number[i] = [i, i^2]

Then you can call the 13^th element of your dictionary:

sage: dict_number[13]
[13, 169]

Note that the keys of your dictionary can be more than just numbers, for example they can be strings:

sage: dict_number['plop'] = [12,13]
sage: dict_number['plop']          
[12, 13]

You can read more about python dictionaries here.

As explained by @Luca, it is not a good idea to have indices as a substring of the name of your lists, but as indices: list_number[i] makes more sense than list_number_i.

Lists indices go from 0 to length-1, so if a is big (or if the set of indices is sparse), you can use a dictionary instead. For example, assume that the i^th element (more precisely the element whose key is i) of your dictionary is the list [i,i^2], you can write:

sage: a = 10
sage: b = 20

sage: dict_number = {}
sage: for i in srange(a, b+1, 1):
....:     dict_number[i] = [i, i^2]

Then you can call the 13^th element of your dictionary:dictionary whose key is 13:

sage: dict_number[13]
[13, 169]

Note that the keys of your dictionary can be more than just numbers, for example they can be strings:

sage: dict_number['plop'] = [12,13]
sage: dict_number['plop']          
[12, 13]

You can read more about python dictionaries here.