If $p$ is a prime, then GF(p^n,'x') is obtained by computing $F_p / (f(x))$ where $f$ is a monic, irreducible polynomial of degree $n$ in $F_p[x]$. For $n=1$, you just get $F_p[x] / (x) \cong F_p$.
So, for any prime $p$, GF(p,'x') is [0,1,2,...,p-1].
If $p$ is a prime, then GF(p^n,'x') is obtained by computing $F_p$F_p[x] / (f(x))$where$f$is a monic, irreducible polynomial of degree$n$in$F_p[x]$. For$n=1$, you just get$F_p[x] / (x) \cong F_p$. So, for any prime$p\$, GF(p,'x') is [0,1,2,...,p-1].