1 | initial version |

I am new to sage. So, sorry if my question is trivial.

Not at all! Likely you could have found this by doing a little more reconnaissance, but hopefully others in the same boat will now find this instead.

Incidentally, `x`

is the only predefined variable, so your first line is not needed. Also, the semicolons are not necessary to suppress output.

I hope this example answers your questions.

```
sage: f = x^2 - 5*x + 6
sage: z = solve(f,x) # f==0 is implicit
sage: z
[x == 3, x == 2]
sage: z[0]
x == 3
sage: z[1]
x == 2
sage: z[0].rhs()
3
sage: z[0].lhs()
x
```

Essentially, Sage returns Python lists, and this is how to extract stuff from them. It returns a symbolic equality, and then the `rhs()`

method gets the "right hand side".

There is another way to get solutions as Python dicts, but that is slightly more advanced so maybe someone else can comment on that.

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