# Revision history [back]

So that this is recorded somewhere, here's the simplest way I found (thanks @kcrisman-- I always forget that we can access maxima functionality). It turns out maxima's subst is pretty powerful:

sage: var("x a")
(x, a)
sage: f = 10*x+3
sage: f
10*x + 3
sage: maxima.subst(a, 10, f).sage()
a*x + 3


but then you have to live with any changes induced on the trip, whereas with Mike's solution you don't have to worry about that, and you can replace the "==" comparison by something which is as finely-tuned as you want.

I'd like f.subs({10:a}) to work, but I get lost in the code as soon as _gobjs start showing up..