1 | initial version |

The `w`

in `sin(t*w)`

does not refer to whatever the object with identifier `w`

in the current scope. There isn't a way to get Python to work like this. You need to do something like:

```
sage: var('t w')
(t, w)
sage: f(t) = sin(w*t)
sage: f.subs(w=2).function(t)
t |--> sin(2*t)
```

2 | Change to accommodate the author's revision. |

The `w`

in `sin(t*w)`

does not refer to whatever the object with identifier `w`

in the current scope. There isn't a way to get Python to work like this. You need to do something like:

`sage: `~~var('t ~~var('t, w')
(t, w)
sage: ~~f(t) ~~f(a,b,c,d,e,f,g,t) = ~~sin(w*t)
~~sin(t*w)
sage: ~~f.subs(w=2).function(t)
t ~~f.subs(w=2).function(*f.arguments())
(a, b, c, d, e, f, g, t) |--> sin(2*t)

3 | No.3 Revision |

The `w`

in `sin(t*w)`

does not refer to whatever the object with identifier `w`

in the current scope. There isn't a way to get Python to work like this. You need to do something like:

```
sage: var('t, w')
(t, w)
sage: params = {w: 2}
sage: f(a,b,c,d,e,f,g,t) = sin(t*w)
sage:
```~~f.subs(w=2).function(*f.arguments())
~~f.subs(params).function(*f.arguments())
(a, b, c, d, e, f, g, t) |--> sin(2*t)

You just have to define the replacements you want once in a dictionary. You still have to call subs once for every function you want to change.

4 | Took kcrisman's answer into account. |

`w`

in `sin(t*w)`

does not refer to whatever the object with identifier `w`

in the current scope. There isn't a way to get Python to work like this. You need to do something like:

```
sage: var('t, w')
(t, w)
sage: params = {w: 2}
sage: f(a,b,c,d,e,f,g,t) = sin(t*w)
sage:
```~~f.subs(params).function(*f.arguments())
~~f.subs(params)
(a, b, c, d, e, f, g, t) |--> sin(2*t)

You just have to define the replacements you want once in a dictionary. You still have to call subs once for every function you want to change.

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