Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.
| 2013-01-29 23:36:18 +0200 | asked a question | linear algebra point and line I have been having difficulty with this problem. Any help would be appreciated. Consider a line L which goes by a point Q and is parallel to a vector v. Let P be any point and let R be its mirror image across the line L. (a) Find a formula for R starting from P, Q and vector v. Sketch your construction. (b) Assume that P(1, 6, 2), Q(-4, 1, 2) and vector v = <-2,-1,5>. Find R. |
| 2013-01-29 23:34:42 +0200 | asked a question | finding specific vectors froma parallelogram I have no idea what to do for this problem. Any help would be appreaciated. Consider the parallelogram of the following picture. a) Rewrite the following cross products using (vector v) cross product (vector w). Simplify your answers. i) (vector AB) cross product (vector AC) ii) (vector AC) cross product (vector AD) iii) (vector AB) cross product (vector DC) iv) (vector AC) cross product (vector BD) (b) For each of the following pairs of vectors, draw the original parallelogram and a new parallelogram whose sides are equal to the given vectors. Use these parallelograms to explain geometrically the corresponding algebraic result of (a). i) vector AB, vector AC ii) vector AC, vector AD iv) vector AC, vector BD |
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.