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I'm trying to solve a toy linear system. Why does the result depend on the order of variables and on the repetition of the equations?

sage: var("x,y")

(x, y)

sage: solve([y==0],x,y)

([], [])

sage: solve([y==0],y,x)

([y == 0], [1])

sage: solve([y==0,y==0],x,y)

[[x == r3, y == 0]]

I'm trying to solve a toy linear system. Why does the result depend on the order of variables and on the repetition of the equations?

sage: var("x,y")
 
var("x,y")
(x, y)
 
y)
sage: solve([y==0],x,y)
 
solve([y==0],x,y)
([], [])
 
[])
sage: solve([y==0],y,x)
 
solve([y==0],y,x)
([y == 0], [1])
 
[1])
sage: solve([y==0,y==0],x,y)
 
solve([y==0,y==0],x,y)
[[x == r3, y == 0]]0]]

I'm trying to solve a toy linear system. Why does the result depend on the order of variables and on the repetition of the equations?

sage: var("x,y")
(x, y)
sage: solve([y==0],x,y)
([], [])
sage: solve([y==0],y,x)
([y == 0], [1])
sage: solve([y==0,y==0],x,y)
[[x == r3, y == 0]]

I'm trying to solve a toy linear system. Why does the result depend on the order of variables and on the repetition of the equations?

sage: var("x,y")
(x, y)
sage: solve([y==0],x,y)
([], [])
sage: solve([y==0],y,x)
([y == 0], [1])
sage: solve([y==0,y==0],x,y)
[[x == r3, y == 0]]