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2012-05-28 04:37:19 +0200 | commented answer | Polynomial identity Cool! I actually managed myself to write a slightly different version of your code. Great. I really thank you for your help ^^'. |
2012-05-27 20:22:30 +0200 | commented answer | Polynomial identity First of all I thank you for your interest. I knew nothing about Sage till today's evening. I tried to type your code directly into the console, but something happens at line 8. Is any way I can include this function in the core of the program so that I don't need to define it everytime from console (just in case I am able to do so...). I mainly understand your code even I know nothing about this language nor its functions. Any comment that lead to understanding would be really appreciated. |
2012-05-27 12:13:33 +0200 | received badge | ● Editor (source) |
2012-05-27 11:53:59 +0200 | asked a question | Polynomial identity I'm pretty interested in solving the following kind of problem using Sage: ``Let R be a polynomial ring in, say, x,y,z as variables over a field k. I'd like to find field-elements a,b,c such that a(x^2+y^2)+b(xy+zx)+c(xyz)==0, if they exist (I know they do)'' so that Sage returns (a,b,c)=(0,0,0). That seems to be an easy matter if one can traduce the polynomial identity into a vector space identity. I proved to be unable to do so. I've to say that my polynomial identities are quite more cumbersome and include up to 7 variables so working them by-hand is almost impossible in a finite ammount of time or patience. |