2015-02-18 16:28:57 -0500 received badge ● Famous Question (source) 2015-01-13 14:26:44 -0500 received badge ● Taxonomist 2013-12-05 04:12:00 -0500 received badge ● Notable Question (source) 2013-07-04 02:25:19 -0500 received badge ● Popular Question (source) 2012-04-19 17:59:02 -0500 commented answer Set global precision for reals? I was searching anything like this for a long time!! Thanks a lot :) PS: Sorry for my english, that is not my mother tongue. 2012-04-19 11:06:05 -0500 commented answer How can I find the maximum of a two variable function? Yes!! This works perfectly! Thanks a lot :) 2012-04-19 11:05:45 -0500 received badge ● Scholar (source) 2012-04-19 11:05:45 -0500 marked best answer How can I find the maximum of a two variable function? I just took a few minutes to modify the example from this page http://www.sagemath.org/doc/reference... I apologize in advance if there is a mistake. Basically there isn't a function to maximize with constraint. So what we can do is minimize the negative of the function. The constraints are of the for '>0' for example c_1 tells the solver that x>0, c_2 tells that -x+1 > 0 => x<1 and so on f = lambda p: - p*p + p*p c_1 = lambda p: p c_2 = lambda p: - p + 1 c_3 = lambda p: p c_4 = lambda p: -p + 2 a = minimize_constrained(f,[c_1, c_2,c_3,c_4],[0.5,0.5]) view(a) The answer I get is (1.0,0.5001) If I plot the negative of the function in the range you are interested, the minimum looks like it is around that. Let me know if this works. 2012-04-11 18:24:00 -0500 received badge ● Student (source) 2012-04-11 15:45:26 -0500 received badge ● Supporter (source) 2012-04-11 15:35:03 -0500 asked a question How can I find the maximum of a two variable function? Hello everyone, I'm trying to find the maximum of the following function: var('x,y') func(x,y) = x*y - y^2 Is there any way I can find the maximum of that function (func) when 0 < x < 1 and 0 < y < 2 for example? Thanks in advance :)