2020-12-04 18:05:00 +0200 | received badge | ● Notable Question (source) |

2019-02-16 21:08:36 +0200 | received badge | ● Notable Question (source) |

2019-02-16 21:08:36 +0200 | received badge | ● Popular Question (source) |

2017-06-16 18:13:54 +0200 | received badge | ● Notable Question (source) |

2017-04-04 23:19:12 +0200 | received badge | ● Popular Question (source) |

2016-02-28 17:13:46 +0200 | received badge | ● Popular Question (source) |

2015-03-27 04:09:38 +0200 | marked best answer | Use a symbolic solved variable in another later equation So I just started using sage but I can't find this (or I don't know how to formulate it). I have an equation that I solved and I want to use that solved variable in a new equation: but this doesn't work and of course I can do c/b but then it just gives me c/b and I want c/(d-a) as an answer. |

2014-09-02 17:18:30 +0200 | commented answer | Solve for variable but variable is still in answer Why do you subtract eq7c rhs from lhs **=^ |

2014-08-29 21:53:25 +0200 | received badge | ● Supporter (source) |

2014-08-29 19:21:31 +0200 | commented answer | Solve for variable but variable is still in answer And there are no other options to solve this? I know there are two solutions (quadratic rule) but I take only one with the eq6[0].rhs() right? |

2014-08-29 17:50:42 +0200 | commented question | complex substitution Yeah, I understand, but I wanted to avoid making 1000 threads |

2014-08-29 17:12:33 +0200 | commented question | complex substitution That's not entirely true since the edit here was about another substitution, the other one was about solving for a variable which gave me an answer where the variable is not isolated. |

2014-08-29 15:48:42 +0200 | commented question | Solve for variable but variable is still in answer I forgot to copy that line or something, sorry about that |

2014-08-28 22:39:48 +0200 | commented question | Solve for variable but variable is still in answer It looks like it sees P3 and P3 as different variables? |

2014-08-28 22:39:15 +0200 | received badge | ● Commentator |

2014-08-28 19:49:41 +0200 | asked a question | Solve for variable but variable is still in answer I try to solve for variable P3. Sage gives me an answer for P3 but it still contains P3 on the right hand side (see last equation after the solve in the beginning of sqrt? |

2014-08-28 16:18:53 +0200 | commented answer | complex substitution Ah okay I think I get it! Great thanks for the elaborate answer! What is the difference between .subs and .subs_expr? |

2014-08-28 00:05:30 +0200 | received badge | ● Student (source) |

2014-08-27 21:53:29 +0200 | edited question | complex substitution Im working on a loooooooooooooong formula. I want to replace (substitute?) certain combination of variables for another simpeler combination of variables (like for example F=m*a), anywhere in the formula where this combination exists. Case 1 (Works): I have a formula let say (doesnt work with the multiplication? just gives me the same answer as i had without the substitution) Edit: Case 2 (solved): so it does some kind of operation on equation 2 but I want to replace the a in equation 2 for equation 1 my code: The last one i want to turn the a3r3u3 into the longer one, but it just gives me back a3r3u3 |

2014-08-27 15:28:19 +0200 | commented question | complex substitution I expected that result, but if i try this with my own formula it gives me back (a*m+f)/g And im doing it the exact same way except that there are more variables involved. Does sage see that if something is squared or multiplied with something else it can be taken apart? |

2014-08-26 23:00:15 +0200 | commented question | complex substitution When I use the .subs_expr it doesn't give me back anything |

Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.