2020-12-04 18:05:00 +0200 received badge ● Notable Question (source) 2019-02-16 21:08:36 +0200 received badge ● Notable Question (source) 2019-02-16 21:08:36 +0200 received badge ● Popular Question (source) 2017-06-16 18:13:54 +0200 received badge ● Notable Question (source) 2017-04-04 23:19:12 +0200 received badge ● Popular Question (source) 2016-02-28 17:13:46 +0200 received badge ● Popular Question (source) 2015-03-27 04:09:38 +0200 marked best answer Use a symbolic solved variable in another later equation So I just started using sage but I can't find this (or I don't know how to formulate it). I have an equation that I solved and I want to use that solved variable in a new equation: a, b, c, d = var('a b c d') eq1=a+b==d eq2=solve([eq1],b) eq3=c/eq2  but this doesn't work and of course I can do c/b but then it just gives me c/b and I want c/(d-a) as an answer. 2014-09-02 17:18:30 +0200 commented answer Solve for variable but variable is still in answer Why do you subtract eq7c rhs from lhs **=^ 2014-08-29 21:53:25 +0200 received badge ● Supporter (source) 2014-08-29 19:21:31 +0200 commented answer Solve for variable but variable is still in answer And there are no other options to solve this? I know there are two solutions (quadratic rule) but I take only one with the eq6[0].rhs() right? 2014-08-29 17:50:42 +0200 commented question complex substitution Yeah, I understand, but I wanted to avoid making 1000 threads 2014-08-29 17:12:33 +0200 commented question complex substitution That's not entirely true since the edit here was about another substitution, the other one was about solving for a variable which gave me an answer where the variable is not isolated. 2014-08-29 15:48:42 +0200 commented question Solve for variable but variable is still in answer I forgot to copy that line or something, sorry about that 2014-08-28 22:39:48 +0200 commented question Solve for variable but variable is still in answer It looks like it sees P3 and P3 as different variables? 2014-08-28 22:39:15 +0200 received badge ● Commentator 2014-08-28 19:49:41 +0200 asked a question Solve for variable but variable is still in answer I try to solve for variable P3. Sage gives me an answer for P3 but it still contains P3 on the right hand side (see last equation after the solve in the beginning of sqrt? sage: A1, A2, A3, P1, P2, P3, u1, u2, u3, r1, r2, r3, g, C, M1, M2, M3 = var('A1 A2 A3 P1 P2 P3 u1 u2 u3 r1 r2 r3 g C M1 M2 M3') sage: eq1=A3*(P1-P3)==A3*r3*u3^2-(A2*r2*u2^2+A1*r1*u1^2) sage: eq2=A3*u3*r3==A2*u2*r2+A1*r1*u1 sage: eq5a=solve([eq2],r3) sage: eq5b=u3^2+2*g/(g-1)*(P3/(eq5a[0].rhs()))-2*C==0 sage: eq6=solve([eq5b],u3) sage: eq7a=eq1/A3 sage: eq7b=eq7a.subs(-A3*r3*u3^2 == -(A2*u2*r2+A1*r1*u1)*u3) sage: eq7b P1 - P3 == -(A1*r1*u1^2 + A2*r2*u2^2 + (A3*P3*g + sqrt(A3^2*P3^2*g^2 + 2*((g^2 - 2*g + 1)*A1^2*r1^2*u1^2 + 2*(g^2 - 2*g + 1)*A1*A2*r1*r2*u1*u2 + (g^2 - 2*g + 1)*A2^2*r2^2*u2^2)*C))*(A1*r1*u1 + A2*r2*u2)/(A1*(g - 1)*r1*u1 + A2*(g - 1)*r2*u2))/A3 sage: eq7c=eq7b.subs(u3==eq6[0].rhs()) sage: eq7=solve([eq7c],P3) sage: eq7 [P3 == (A1*r1*u1^2 + A2*r2*u2^2 + A3*P1 - (A1*r1*u1^2 + A2*r2*u2^2 + A3*P1)*g - sqrt(A3^2*P3^2*g^2 + 2*((g^2 - 2*g + 1)*A1^2*r1^2*u1^2 + 2*(g^2 - 2*g + 1)*A1*A2*r1*r2*u1*u2 + (g^2 - 2*g + 1)*A2^2*r2^2*u2^2)*C))/A3]  2014-08-28 16:18:53 +0200 commented answer complex substitution Ah okay I think I get it! Great thanks for the elaborate answer! What is the difference between .subs and .subs_expr? 2014-08-28 00:05:30 +0200 received badge ● Student (source) 2014-08-27 21:53:29 +0200 edited question complex substitution Im working on a loooooooooooooong formula. I want to replace (substitute?) certain combination of variables for another simpeler combination of variables (like for example F=m*a), anywhere in the formula where this combination exists. Case 1 (Works): I have a formula let say sage: eq1=m*a==(b+c)*k sage: eq2=d==a*m+f sage: eq3=eq2.subs(eq1)/g  (doesnt work with the multiplication? just gives me the same answer as i had without the substitution) Edit: Case 2 (solved): so it does some kind of operation on equation 2 but I want to replace the a in equation 2 for equation 1 my code: sage: A1, A2, A3, P1, P3, u1, u2, u3, r1, r2, r3 = var('A1 A2 A3 P1 P3 u1 u2 u3 r1 r2 r3') sage: eq7a = P1 - P3 == -(A1*r1*u1^2 + A2*r2*u2^2 - A3*r3*u3^2)/A3 sage: eq7a.subs_expr(A3*r3*u3^2 == (A2*u2*r2 + A1*r1*u1)*u3) sage: A1, A2, A3, P1, P3, u1, u2, u3, r1, r2, r3 = var('A1 A2 A3 P1 P3 u1 u2 u3 r1 r2 r3') sage: eq7a = P1 - P3 == -(A1*r1*u1^2 - A2*r2*u2^2 + A3*r3*u3^2)/A3 sage: eq7a.subs_expr(A3*r3*u3^2 == (A2*u2*r2 + A1*r1*u1)*u3)  The last one i want to turn the a3r3u3 into the longer one, but it just gives me back a3r3u3 2014-08-27 15:28:19 +0200 commented question complex substitution I expected that result, but if i try this with my own formula it gives me back (a*m+f)/g And im doing it the exact same way except that there are more variables involved. Does sage see that if something is squared or multiplied with something else it can be taken apart? 2014-08-26 23:00:15 +0200 commented question complex substitution When I use the .subs_expr it doesn't give me back anything