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2012-05-04 13:13:12 +0100 | answered a question | check if the result is a real number again, this works perfect :) |
2012-05-04 13:12:16 +0100 | commented answer | check if the result is a real number for self reference, this is what I got: |
2012-05-04 13:08:14 +0100 | marked best answer | check if the result is a real number I think " For testing integrality, or rationality, " And if you know the numbers you're checking are complex, you could also test to see whether their imaginary parts are zero. |
2012-05-04 13:05:48 +0100 | commented answer | check if the result is a real number Thanks so much :) |
2012-05-04 12:39:24 +0100 | asked a question | check if the result is a real number I get several results and want to check, which one is a real number. From trial and error, I can see that maxSol[2][x] is the only plausable solution. Is there something like isReal()? my attempt (don't laugh) ;) for i in maxSol: print RealField(50)(i) where I obviously get: TypeError: Unable to convert x (='..... |
2012-03-01 10:08:52 +0100 | commented answer | solving sqrt(-1) to a real number that works perfect, thanks :) |
2012-03-01 10:08:34 +0100 | marked best answer | solving sqrt(-1) to a real number sage: A(x)=x/2+(4-x*x)^(1/2) sage: solve(diff(A(x),x),x,to_poly_solve=true) [x == 2/5*sqrt(5)] |
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2012-03-01 09:26:06 +0100 | asked a question | solving sqrt(-1) to a real number Here is what I am trying to do: and get i multiplied by the root of x^2... if I put the same equation into wolfram, it gives me a real number 2/sqrt(5) (which is correct and makes sense). How can I make SageMath solve those? I tried simplify() and full_simplify(), maxima_methods() and rootscontract() gives an error in combination with solve(). I guess it's just some syntax error, sorry for that :( For now I do most in the Sage - Cell Server, which is great. |