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2014-06-28 20:15:17 -0500 | marked best answer | Permutation group: (1234)=(12)(13)(14) How do I show in sage that I tried make use of: but it doesn't do what is needed. |

2014-06-28 20:15:17 -0500 | marked best answer | S3's elements Here's elements of Symmetric group of 6th order: S3: I want to get the same in Sage. So I do: Now I can't find (1,3,2) element in the book. As far as I understand: So my question is to set the correct map from sage to my book... |

2014-06-28 20:15:17 -0500 | marked best answer | What can I delete? So I've compiled sage from sources. The sage folder is now 3Gb. I guess I've no need for some files... What can I delete? Is there any reason I should not delete these things? |

2014-06-28 20:14:50 -0500 | marked best answer | Symbolic product in Sage? Suppose I'd like to compute How can this be done? I found an old thread, but with no answers. |

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2013-06-16 00:38:35 -0500 | marked best answer | Symbolic product in Sage? Take the natural logarithm of your product and you get a sum which can be evaluated: $$\ln\left( \prod_{x=1}^k \frac{1}{x^4} \right) = \sum_{x=1}^k \ln\left(\frac{1}{x^4}\right)$$ ... now take the limit as $k \to \infty$: |

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2012-06-18 23:39:28 -0500 | commented question | Python thing that doesn't work in Sage, works in pure Python See [here](http://www.sagemath.org/doc/faq/faq-usage.html#i-have-type-issues-using-scipy-cvxopt-or-numpy-from-sage). |

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2012-06-14 04:23:20 -0500 | commented answer | Symbolic product in Sage? Am... Great, but why post it here? |

2012-06-13 03:37:57 -0500 | marked best answer | Check that P3*P6=P4 The problem is that you are comparing By the way, they're not the same. But that's a different issue. They're using the notation of the second row of your notation in your original question, not cycle notation. |

2012-06-12 07:45:50 -0500 | commented answer | Check that P3*P6=P4 But mine are also the same. [3, 2, 1] is same as [2, 1, 3], isn't it? |

2012-06-12 07:18:09 -0500 | asked a question | Check that P3*P6=P4 Here's elements of Symmetric group of 6th order: S3: I want to check that P3*P6=P4. it gives: so they are the same actually. But how do I make sage say |

2012-06-12 05:52:41 -0500 | marked best answer | S3's elements The results of are given in cycle notation. So the book's equivalent of (1,3,2) is one where 1 becomes 3, 3 becomes 2, and 2 becomes 1, which is P6, if I'm reading correctly. If you want to match the bottom three elements of your matrix, you can simply convert each to a list, or maybe a dict would make the mapping more explicit: |

2012-06-12 05:52:40 -0500 | commented answer | S3's elements That's very cool. I did this: `for e in sorted(G): print '{0:>8s}{1:>10s}{2:>19s}'.format(e, e.list(), e.dict())` (I type more then, but it inserts >...) |

2012-06-12 05:47:52 -0500 | commented answer | Polynomial representation of GF(7)? Oh I see - so it's just because `n=1`. Thank You for Your answer. |

2012-06-12 05:47:31 -0500 | marked best answer | Polynomial representation of GF(7)? If $p$ is a prime, then So, for any prime $p$, |

2012-06-12 03:49:54 -0500 | commented question | separation of variables / parameterizing equations in sage math I'd've recommend You to read 'symbolic expression' of reference manual. Take a look at `collect`, lhs(), rhs() there. |

2012-06-12 03:45:31 -0500 | marked best answer | Permutation group: (1234)=(12)(13)(14) Sage's built-in help is useful here. So indeed you get a permutation group, with these things as generators. You can't multiply groups. A similar look at help will show you that But you |

2012-06-12 03:38:30 -0500 | asked a question | Polynomial representation of GF(7)? Why sage would give me polynomial representation of GF(8), but not GF(7)? Maybe there's no such thing as polynomial represenation of GF(7)? |

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