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2013-06-18 01:01:46 +0200 | answered a question | integrate cos(x)*cos(2x)*...*cos(mx) via SAGE So the answer is - Yes. It is a bug in algorithm='maxima', so use algorithm='mathematica_free' (def new function to find definite integral) or simplify_full() for such product of cos(kx) and than integrate. |
2013-06-18 00:51:12 +0200 | commented question | integrate cos(x)*cos(2x)*...*cos(mx) via SAGE Thanks! Really if use simplify_full() than answer is correct |
2013-06-18 00:49:45 +0200 | commented question | How to use algorithm='mathematica free' to calculate definite integral? Thanks for comments! |
2013-06-18 00:49:19 +0200 | answered a question | How to use algorithm='mathematica free' to calculate definite integral? Thanks for comments! And output: 1/3 |
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2013-06-17 15:46:01 +0200 | asked a question | How to use algorithm='mathematica free' to calculate definite integral? Is it possible to use algorithm='mathematica free' to calculate definite integral ? Output: and Output: but I want 1/3 |
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2013-06-17 13:39:21 +0200 | asked a question | integrate cos(x)*cos(2x)*...*cos(mx) via SAGE I'm going to find $I_m=\int_0^{2\pi} \prod_{k=1}^m cos(kx){}dx$, where $m=1,2,3\ldots$ Simple SAGE code: Output: As you can see numerical answer is right, but result of integrate(...) is right for $m=1,2,\ldots,7$ and then there is some bug. We can print indefinite integral: And Output: (more) |
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