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2011-06-27 12:19:04 +0200	marked best answer	Factorial simplification error I made this ticket 11539. As a temporary workaround, you can run the following commands which should fix things. `sage.calculus.calculus.maxima.eval(r":lisp (defun msize-factorial (x l r) (setq l (msize (cadr x) (revappend '(#\f #\a #\c #\t #\o #\r #\i #\a #\l #\() l) nil 'mparen 'mparen) r (list 1 #\) ) ) (list (+ (car l) (car r)) l r)) ") sage.calculus.calculus.maxima.eval(r":lisp (defprop mfactorial msize-factorial grind)")` This changes things in Maxima so that `factorial(x)` is printed as `factorial(x)` instead of `x!`.
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2011-06-23 16:17:42 +0200	asked a question	Factorial simplification error I've run into an issue when running simplify on an equation containing a factorial: `sage: var('n') sage: z1 = (-1)^(1/2(n - 1))factorial(n) == 0 sage: z2 = 0 == (-1)^(1/2(n - 1))factorial(n) sage: z1.simplify() n(-1)^(1/2n - 1/2) != 0 sage: z2.simplify() 0 == (-1)^(1/2n - 1/2)factorial(n)` My best guess is when sage sends the equation down to maxima for simplification it's interpreting `(-1)^(1/2(n - 1))n! = 0` as `(-1)^(1/2(n - 1))n != 0` Any ideas on how I can work around this?