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2011-06-24 07:54:32 +0100 | marked best answer | how to properly substitute in a matrix? Try this: Or this: I'm not sure exactly what output you are looking for. The documentation for |

2011-06-24 07:54:23 +0100 | commented answer | how to properly substitute in a matrix? Thanks, kcrisman! Maybe it is possible to include these lines into Sage Reference Manual? In the manual one enters the point manually... I don't know how to do this... |

2011-06-24 07:52:04 +0100 | commented answer | how to properly substitute in a matrix? Thanks, niles! |

2011-06-23 13:12:36 +0100 | asked a question | how to properly substitute in a matrix? Let's consider a modified example from Sage reference manual How can i properly substitute the_solution into H? I have tried: H(x,y).subs(the_solution) - does not work. This will work for H(x,y).subs(x==0) H(x,y).subs_expr(*the_solution) - does not work. This will work for f(x,y).subs_expr(*the_solution) |

2011-06-18 11:49:10 +0100 | commented answer | latex typesetting for derivatives like g' Thanks! Will try... |

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2011-06-18 11:48:47 +0100 | marked best answer | latex typesetting for derivatives like g' You can try to apply the patch attached to ticket #6344. The patch review walk through contains instructions on how to apply patches. |

2011-06-17 14:29:02 +0100 | asked a question | latex typesetting for derivatives like g' When i try: i get: but i would like to get something like: How can i do this with Sage? |

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