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2011-06-24 00:54:32 -0600 | marked best answer | how to properly substitute in a matrix? Try this: Or this: I'm not sure exactly what output you are looking for. The documentation for |

2011-06-24 00:54:23 -0600 | commented answer | how to properly substitute in a matrix? Thanks, kcrisman! Maybe it is possible to include these lines into Sage Reference Manual? In the manual one enters the point manually... I don't know how to do this... |

2011-06-24 00:52:04 -0600 | commented answer | how to properly substitute in a matrix? Thanks, niles! |

2011-06-23 06:12:36 -0600 | asked a question | how to properly substitute in a matrix? Let's consider a modified example from Sage reference manual How can i properly substitute the_solution into H? I have tried: H(x,y).subs(the_solution) - does not work. This will work for H(x,y).subs(x==0) H(x,y).subs_expr(*the_solution) - does not work. This will work for f(x,y).subs_expr(*the_solution) |

2011-06-18 04:49:10 -0600 | commented answer | latex typesetting for derivatives like g' Thanks! Will try... |

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2011-06-18 04:48:47 -0600 | marked best answer | latex typesetting for derivatives like g' You can try to apply the patch attached to ticket #6344. The patch review walk through contains instructions on how to apply patches. |

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2011-06-17 07:29:02 -0600 | asked a question | latex typesetting for derivatives like g' When i try: f(x) = function('f',x) g = diff(f(x),x) latex(g) I get: D[0]\left(f\right)\left(x\right) But i would like to get something like: g'\left(x\right) How can i do this with sage? |

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