paulkoer's profile - activity

Benjamin, thanks for this hint, very useful!

Here is a stupid method:

var('x,y')
f(x) = log(x)
g(x) = solve(x == f(y), y)[0].rhs()
print g

Here is a compilation from several scattered sources:

• Sage can compute the inverse of a power series. See:
  • link:Reference Manual
  • link:sage-support discussion
  • link:trac #7644 (closed)
• Somebody once asked for the derivative of the inverse of a general symbolic function, but nobody could figure out how to find just the inverse:
  • link:sage-support discussion
• Mathematica has what you are looking for:
  • link:InverseFunction

Thank you Kelvin! Your 'solve' method works for me. As for the Mathematica method, by using Sage I hope to avoid having to pay for a Mathematica license.

Hello Sage community,

is it possible to compute the inverse of a function in one variable with sage? So say I have

f(x) = log(x)

and I want to compute

f.inverse()

Thank you Paul