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Instead, solve(e^derivative(-x*log(x) -(1-x)*log(1-x),x)==1,x) gives [x == (1/2)]

Instead, solve(e^derivative(-x*log(x) -(1-x)*log(1-x),x)==1,x) gives [x == (1/2)]

symbolic functions and expressions Suppose I have a huge expression involving symbolic variables and symbolic functions.

Representation of Clifford algebras Is there a way of defining a matrix representation of Clifford algebras in sage? F

Representation of Clifford algebras Is there a way of defining a matrix representation of Clifford algebras in sage? F

Representation of Clifford algebras Is there a way of defining a matrix representation of Clifford algebras in sage? F

The output size in jupyter notebook can be changed using this workaround.

fast_callable is very handy for evaluating symbolic expressions with numpy arrays. Like

my_expr = integral(sin(x),x)
f = fast_callable(my_expr, vars=[x])

import numpy as np
z = np.linspace(0,10,5)
f(z)

However, it does't work when the expression involves a special function.

my_expr2 = integral(sin(x^2),x)
g = fast_callable(my_expr2, vars=[x])
g(z)

Throws The Function erf does not support numpy arrays as arguments.

Is there any way of turn symbolic expressions containing special functions into numpy-callable? Thus avoiding to rewrite them using scipy special functions?

I see, thanks!

For expressions with only elementary functions, there is no need of substitute_function. A callable function (or fast_ca

For expressions with only elementary functions, there is no need of substitute_function. A callable function (or fast_ca

fast_callable x numpy fast_callable is very handy for evaluating symbolic expressions with numpy arrays. Like my_expr =

Very nice and informative answer! There is also the GNU Texmacs. It can run sage, R, python, maxima and a bunch of other

You can avoid the TypeError by using the following python function def formal_diff(f, x): tempX = SR.temp_var()

Why not put the variables in a list? some_variables = [var(f'p_{k}{l}') for k in range(5) for l in range(4,8)] for v in

See the chapter 2 of the free book Computational Mathematics with SageMath, it's an excellent introduction to the sage s

I found a workaround for now. First save as html var('u v') some_plots = parametric_plot3d([(cos(u) * sin(v))^3,

I found a workaround for now. First save as html var('u v') some_plots = parametric_plot3d([(cos(u) * sin(v))^3,

I found a workaround for now. First save as html some_plots = parametric_plot3d([(cos(u) * sin(v))^3, (sin(u) * sin(

I found a workaround that works for now. First save as html some_plots = parametric_plot3d([(cos(u) * sin(v))^3, (si

Height of the output cell in 3D plots Is it possible to change the height of the output cell in 3d plots? We can globa

By doing $\sqrt{-\frac{1}{f\left(r\right)^{2} \sin\left(r\right)^{2}}} - \frac{1}{\sqrt{-f\left(r\right)^{2} \sin\left(

For some reason, the solution you found is not exactly the same @CyrilleP found, which is also the one found in find_roo

You can get the dummy variable by dummy_var = sols[0].rhs().variables()[0] And then define a callable function changi

See "E notation" here.

You can get the dummy variable by dummy_var = sols[0].rhs().variables()[0] And then define a callable function changi

Is there any way of extracting a common factor of all terms in a list of symbolic expressions?

For example, in the following list

[x^4*cos(x), x^3*cos(x), x^2*cos(x)*sin(x)]

such function should return x^2*cos(x). And for

 [1/x^4*cos(x), 1/x^3*cos(x), 1/x^2*cos(x)*sin(x)]

it should return 1/x^2*cos(x).

Using the @Max Alekseyev suggestion I was able to write a simple python function that solves the problem. def common_f

Using the Alekseyev suggestion I was able to write a simple python function that solves the problem. def common_factor

Using the Alekseyev suggestion I was able to write a simple python function that solves the problem. def common_factor

Using the Alekseyev suggestion I was able to write a simple python function that solves the problem. def common_factor

Using the Alekseyev suggestion I was able to write a python function that solves the problem. def common_factor(expr_l

common factor in symbolic expressions Is there any way of extracting a common factor of all terms in a list of symbolic

My initial example wasn't that good. For [1/x^4*cos(x), 1/x^3*cos(x), 1/x^2*cos(x)*sin(x)] it should return 1/x^2*co

My initial example wasn't that good. For [1/x^4*cos(x), 1/x^3*cos(x), 1/x^2*cos(x)*sin(x)] is should return 1/x^2*co