Ask Your Question

Nalt's profile - activity

2023-12-31 13:41:28 +0200 received badge  Notable Question (source)
2022-02-10 17:09:14 +0200 received badge  Popular Question (source)
2020-06-28 02:19:31 +0200 asked a question Factoring a symbolic polynomial

The following code:

llambda, mu = var('λ, μ')
uVars = list(var(', '.join([f'u{n}' for n in range(1, 3 + 1)])))
aVars = list(var(', '.join([f'a{n}' for n in range(1, 3 + 1)])))

U = Matrix([[0, -uVars[2], uVars[1]],
            [uVars[2], 0, -uVars[0]],
            [-uVars[1], uVars[0], 0]])
a = Matrix([[aVars[0], 0, 0],
            [0, aVars[1], 0],
            [0, 0, aVars[2]]])
I = matrix.identity(3)

L = a*llambda + U

# Characteristic polynomial

charPoly = det((L - mu*I))
factor(charPoly)

computes a characteristic polynomial and yields:

a1*a2*a3*λ^3 - a1*a2*λ^2*μ - a1*a3*λ^2*μ - a2*a3*λ^2*μ
+ a1*u1^2*λ + a2*u2^2*λ + a3*u3^2*λ + a1*λ*μ^2
+ a2*λ*μ^2 + a3*λ*μ^2 - u1^2*μ - u2^2*μ - u3^2*μ - μ^3

However, this is not the simplification I desire. I want this: $$(a_1\lambda - \mu)(a_2\lambda - \mu)(a_3\lambda - \mu) - (u_1^2 + u_2^2 + u_3^2)\mu + (a_1 \mu_1^2 + a_2 u_2^2 + a_3 u_3^2)\lambda$$

Is there a way to obtain that sort of factorization?