2022-08-15 14:10:58 +0100 | received badge | ● Popular Question (source) |
2020-06-04 13:54:49 +0100 | received badge | ● Student (source) |
2020-06-04 11:05:28 +0100 | received badge | ● Supporter (source) |
2020-06-04 11:05:03 +0100 | commented answer | simplifying a symbolic expression Thank you very much Emmanuel Carpentier. I tried this in the main problem (the above version was the simplified version) it works like a charm. |
2020-06-04 11:01:45 +0100 | received badge | ● Scholar (source) |
2020-06-04 08:18:02 +0100 | received badge | ● Editor (source) |
2020-06-04 08:01:15 +0100 | asked a question | simplifying a symbolic expression Hi I am really tired of not being able to see that sage says the following expression is zero. Instead it returns the same expression. Please help how to make sure that I get 0 for the calculation. Thank you. |
2020-04-28 14:59:12 +0100 | received badge | ● Self-Learner (source) |
2020-04-28 14:59:12 +0100 | received badge | ● Teacher (source) |
2020-04-28 14:58:31 +0100 | answered a question | How to define variables so that (x^a)^b simplifies with x^(a*b)? Hi again. With some help I corrected the code as follows: I think the problem was the possibile ambiguity of 0^0. Thanks. |
2020-04-28 14:58:30 +0100 | asked a question | Why wouldn't (x^a)^b cancel with x^(a*b)? Hi all. In my installation I get False for the following code: var('r n'); f=(r^2)^n; g=r^(2*n); bool(f==g); False Do you think I have a missing package or what am I doing awfully wrong can you help please. Thank you. |
2020-04-28 14:58:30 +0100 | asked a question | How to define variables so that (x^a)^b simplifies with x^(a*b)? Hi all I can't find the correct way to define the variables so that in my calculations (x^a)^b simplifies with x^(a*b). The following code returns False: Thank you very much. |
2020-04-28 10:03:44 +0100 | received badge | ● Organizer (source) |