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2020-06-04 11:05:03 +0100 commented answer simplifying a symbolic expression

Thank you very much Emmanuel Carpentier. I tried this in the main problem (the above version was the simplified version) it works like a charm.

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2020-06-04 08:01:15 +0100 asked a question simplifying a symbolic expression

Hi I am really tired of not being able to see that sage says the following expression is zero. Instead it returns the same expression. Please help how to make sure that I get 0 for the calculation. Thank you.

q= var('q',domain='positive');

n= var('n',domain='positive');

k= var('k',domain='positive');

x= var('x',domain='positive');

(((q - 1)*x + 1)^n*q^n - ((q^2 - q)*x + q)^n).simplify_full()

((q - 1)*x + 1)^n*q^n - ((q^2 - q)*x + q)^n
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2020-04-28 14:58:31 +0100 answered a question How to define variables so that (x^a)^b simplifies with x^(a*b)?

Hi again.

With some help I corrected the code as follows:

r= var('r',domain='positive')
var(' n');f(r,n)=(r^2)^n;
g(r,n)=r^(2*n);
bool(f==g);

True

I think the problem was the possibile ambiguity of 0^0. Thanks.

2020-04-28 14:58:30 +0100 asked a question Why wouldn't (x^a)^b cancel with x^(a*b)?

Hi all.

In my installation I get False for the following code:

var('r n'); f=(r^2)^n; g=r^(2*n); bool(f==g);

False

Do you think I have a missing package or what am I doing awfully wrong can you help please.

Thank you.

2020-04-28 14:58:30 +0100 asked a question How to define variables so that (x^a)^b simplifies with x^(a*b)?

Hi all I can't find the correct way to define the variables so that in my calculations (x^a)^b simplifies with x^(a*b).

The following code returns False:

var('r n');
f=(r^2)^n;
g=r^(2*n);
bool(f==g);

Thank you very much.

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