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2020-01-05 00:12:16 +0200	asked a question	symbolic differentiation of unknown function I want to do some formal calculus with unknown functions for the purpose of solving differential equations. Say `F(t) = v(t)t^2`, where `v` is an unknown differentiable function. Then I would like to declare `v` as such and be able to get `F.diff(t) = 2tv+t^2v.diff(t)` It is similar to Ask Sage question 8822 but the solution does not seem to work anymore, as `function()` takes only one argument and not 2 as in the description. Anyone know what the syntax is in 8.9? Or in 9.0, when that becomes available?