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| 2019-04-11 01:07:18 +0200 | asked a question | The function f: ℝ → ℝ defined by f(x) = 7x is onto because for any real number r, we have that r/7 is a real number and f(r/7) = r. Consider the same function defined on the integers g: ℤ → ℤ by g(n) = 7n. Explain why g is not onto ℤ and give one integer that g cannot output |
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.