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2019-01-02 16:12:02 +0100
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2019-01-11 16:25:54 +0100
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2019-01-02 16:14:16 +0100
James1210
I=∫e^x((sin−1x)−3x(3+2x^2)/(1−x^2)^7/2)dx
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2019-01-02 16:12:03 +0100
James1210
I=∫ex(sin−1x−3x(3+2x2)(1−x2)72)dx [closed]
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I=∫e^x((sin−1x)−3x(3+2x^2)/(1−x^2)^7/2)dx
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I=∫e^x((sin−1x)−3x(3+2x^2)/(1−x^2)^7/2)dx
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