2019-06-26 00:45:36 -0600 | received badge | ● Famous Question (source) |

2018-06-08 08:50:45 -0600 | received badge | ● Notable Question (source) |

2018-04-03 14:28:35 -0600 | received badge | ● Popular Question (source) |

2017-07-06 16:11:31 -0600 | received badge | ● Nice Question (source) |

2017-07-06 12:52:52 -0600 | received badge | ● Student (source) |

2017-07-06 10:22:30 -0600 | asked a question | Polynomial Long Division with Variable Coefficients I want to divide the following polynomial (in terms of $t$) with coefficients in terms of $\lambda$. $$(\lambda^6 - 5\lambda^4 + 6\lambda^2 - 1)t^5 + (\lambda^5 - 4\lambda^3 + 3\lambda^2)t^6$$ by $$ \lambda t^2 -\lambda^2 t + \lambda$$ The resulting quotient will include a fractional component (the numerator's degree will be strictly less than the denominator's degree). This is what a quotient and remainder, added together, might look like: $$ t(\frac{2\lambda^8 - 9 \lambda^6 + 2 \lambda^5 + 6 \lambda^4 - 4\lambda^2}{\lambda}) + t^3(\frac{2\lambda^6 - 9\lambda^4 + 3\lambda^3 + 6\lambda^2 -1 }{\lambda}) + \frac{t(\lambda^4 - 2\lambda) + (\lambda^3 - 4\lambda^2)}{\lambda t^2 - \lambda^2 t + \lambda}$$
The code: |

Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.