2019-12-29 12:52:42 -0500 asked a question Partial fraction decomposition over reals Hello. I'm trying to find partial fraction decomposition of 1/(x**2-2*b**2) I use f.partial_fraction(var), but I don't get the result. How can I get an exact answer over the reals in general case? 2019-02-19 15:34:26 -0500 received badge ● Good Question (source) 2018-10-26 15:55:12 -0500 received badge ● Nice Question (source) 2018-10-26 10:02:46 -0500 commented question Indefinite integral is incorrect @tmonteli, I use sage 8.1 2018-10-26 07:08:37 -0500 asked a question Indefinite integral is incorrect indefinite_integral(sqrt(1+cos(x)**2), x).full_simplify() gives 1/6*sin(x)^3, which is incorrect. 2016-12-01 10:48:17 -0500 commented answer Sage incorrectly evaluates series OK. Thank you. 2016-12-01 09:11:02 -0500 commented answer Sage incorrectly evaluates series I've got ValueError: Mathematica cannot make sense of input sum(1/((2*x+1)^2-4)^2,x,0,Infinity, algorithm='mathematica') 2016-12-01 09:02:30 -0500 received badge ● Scholar (source) 2016-12-01 09:02:29 -0500 received badge ● Supporter (source) 2016-12-01 07:57:48 -0500 received badge ● Student (source) 2016-12-01 03:02:43 -0500 asked a question Sage incorrectly evaluates series It incorrectly evaluates $\displaystyle\sum_{n=0}^{\infty}\frac{1}{((2n+1)^2-4)^2}=\frac{\pi^2}{64}-\frac{1}{12}$, but correct answer is $\displaystyle\frac{\pi^2}{64}$ 2016-12-01 03:02:43 -0500 asked a question Sage incorrectly evaluates series It incorrectly evaluates $\displaystyle\sum_{n=0}^{\infty}\frac{1}{((2n+1)^2-4)^2}=\frac{\pi^2}{64}-\frac{1}{12}$, but correct answer is $\displaystyle\frac{\pi^2}{64}$