2016-10-09 10:49:01 +0100 | received badge | ● Self-Learner (source) |
2016-10-09 10:49:01 +0100 | received badge | ● Teacher (source) |
2016-10-01 23:05:17 +0100 | answered a question | Cryptographic Mathematics Update: |
2016-10-01 23:04:16 +0100 | commented question | Cryptographic Mathematics i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i |
2016-10-01 23:02:34 +0100 | commented answer | Cryptographic Mathematics i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i |
2016-10-01 21:38:39 +0100 | received badge | ● Student (source) |
2016-10-01 21:36:54 +0100 | commented answer | Cryptographic Mathematics could you please post the code of Sage? |
2016-10-01 21:18:14 +0100 | asked a question | Cryptographic Mathematics Q: Programme Rowland’s formula and verify his results. Try different starting values and see what happens. In Sage math cloud, I did this: Could you help, please? |
2016-10-01 21:18:14 +0100 | asked a question | Cryptographic Mathematics Q: Programme Rowland’s formula and verify his results. Try different starting values and see what happens. In Sage math cloud, I did this: i=7 n=2 for n in [1..10]: i=i+gcd(n,i) print i Could you help, please? |