2016-10-09 03:49:01 -0500 received badge ● Self-Learner (source) 2016-10-09 03:49:01 -0500 received badge ● Teacher (source) 2016-10-01 16:05:17 -0500 answered a question Cryptographic Mathematics Update: i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i  2016-10-01 16:04:16 -0500 commented question Cryptographic Mathematics i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i 2016-10-01 16:02:34 -0500 commented answer Cryptographic Mathematics i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i 2016-10-01 14:38:39 -0500 received badge ● Student (source) 2016-10-01 14:36:54 -0500 commented answer Cryptographic Mathematics could you please post the code of Sage? 2016-10-01 14:18:14 -0500 asked a question Cryptographic Mathematics Q: Programme Rowland’s formula and verify his results. Try different starting values and see what happens. In Sage math cloud, I did this: i =7 n=2 for n in [1..10]: i=i+gcd(n,i) print i  Could you help, please? 2016-10-01 14:18:14 -0500 asked a question Cryptographic Mathematics Q: Programme Rowland’s formula and verify his results. Try different starting values and see what happens. In Sage math cloud, I did this: i=7 n=2 for n in [1..10]: i=i+gcd(n,i) print i Could you help, please?