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2016-10-09 03:49:01 -0500 received badge  Self-Learner (source)
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2016-10-01 16:05:17 -0500 answered a question Cryptographic Mathematics

Update:

i=7
n=2
for n in range(2,100):
    i=i+gcd(n,i)
    print i
2016-10-01 16:04:16 -0500 commented question Cryptographic Mathematics

i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i

2016-10-01 16:02:34 -0500 commented answer Cryptographic Mathematics

i=7 n=2 for n in range(2,100): i=i+gcd(n,i) print i

2016-10-01 14:38:39 -0500 received badge  Student (source)
2016-10-01 14:36:54 -0500 commented answer Cryptographic Mathematics

could you please post the code of Sage?

2016-10-01 14:18:14 -0500 asked a question Cryptographic Mathematics

Q: Programme Rowland’s formula and verify his results. Try different starting values and see what happens.

In Sage math cloud, I did this:

i =7
 n=2
    for n in [1..10]:
    i=i+gcd(n,i)
    print i

Could you help, please?

2016-10-01 14:18:14 -0500 asked a question Cryptographic Mathematics

Q: Programme Rowland’s formula and verify his results. Try different starting values and see what happens.

In Sage math cloud, I did this:

i=7 n=2 for n in [1..10]: i=i+gcd(n,i) print i


Could you help, please?