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2014-01-22 00:43:46 -0500 | asked a question | sage-mode in emacs I'm trying to get the syntax highlighting to work in emacs. I have tried to install sage-mode following the manual on the https://bitbucket.org/gvol/sage-mode/... This fail on running the first command:
I use Sage Version 5.9. Could someone help me with this please? |

2013-08-29 22:40:04 -0500 | commented question | Long expression in printed-out documents I have the same problem. My equations are way too long to be shown on one line in pdf file. I have tried to export it to LaTeX and split manually, but it is not an easy job to do. Have you found any solution for that? |

2013-08-20 00:06:15 -0500 | commented answer | vector derivative returns a scalar Anyway, I reckon that the first example is probably a bug. The derivative of n-dimensional vector should have n-dimensions again no matter to which ring it belongs to. Would you know how to report that, please? |

2013-08-19 23:57:21 -0500 | marked best answer | vector derivative returns a scalar Look at the help of then you can see that it is considering it as a two dimensional function. In the second case, you have a function of one variable in the variable The alternative fix is to work in the symbolic ring: |

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2013-08-19 23:56:47 -0500 | commented answer | vector derivative returns a scalar Thanks, the fix with a symbolic ring is helpful. In my problem the $\vec{u}$ really is a function, just happens to be a constant at this occasion. |

2013-08-19 05:45:42 -0500 | commented question | vector derivative returns a scalar Compared to: a(x) = function('a',x) b(x) = function('b',x) u = matrix(1,2,[a,b]) r = derivative(u,x);r Which gives a vector as expected: [x |--> D[0](a)(x) x |--> D[0](b)(x)] |

2013-08-19 05:38:26 -0500 | asked a question | vector derivative returns a scalar Trying to obtain the derivative of $\vec{u} = [-1,1]$ using the following code:
I get a scalar value 0. Although according the following relation it should be a 2-dimensional zero vector. $$\frac{\mathrm{d} \vec{u}}{\mathrm{d} x} =\frac{\mathrm{d}}{\mathrm{d} x} [-1, 1] = [ \frac{\mathrm{d}}{\mathrm{d} x}(-1), \frac{\mathrm{d}}{\mathrm{d} x}(1) ] = [0, 0]$$ Why does it happen? In the case it's a bug where could I report it? Thanks |

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2013-08-15 01:36:41 -0500 | answered a question | append a variable to a vector So an solution which work is to convert the vector to a list, append the new variable and convert to a vector again. The code for that would be as follows:
Do you see any potential problems with this solution? Why there is no method append in vector? Could I do better? |

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2013-08-14 23:23:40 -0500 | asked a question | append a variable to a vector I would like to define a new vector in Sage $\vec{u} = [O, P, \sigma]$ using a previously defined vecotor $\vec{x} = [O, P]$ and a new variable $\sigma$. My code looks like:
Which gives an error:
Apparently this is because vector() requires the variables to be of the same ring. In my case
and
There is any way how to connect this two objects ($\vec{x}$, $\sigma$) together to create one vector? |

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