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2020-04-15 18:06:37 +0100 | commented answer | Interact selector containing card suits Thank you, it is great. Also thanks for the second part. |
2020-04-15 15:27:34 +0100 | commented question | Interact selector containing card suits That is what I looked for. It seems that the code works online using SageMath Cell, but not in Jupyter Notebook. |
2020-04-07 11:33:07 +0100 | asked a question | Interact selector containing card suits I have the following code that used to work in the Python 2 era: Now it provides. Is there a way to have the expected symbols in the selector? Thank you for your suggestions in advance. OK, it seems to work online using SageMath Cell, in case of Jupyter Notebook I still do not know an answer. |
2020-02-01 14:48:21 +0100 | received badge | ● Commentator |
2020-02-01 14:48:21 +0100 | commented question | SageTeX: sagecommandline problem You are completely right, thank you. In memoire documentclass it works fine, it is the elegantbook documentclass that makes the problem. |
2020-01-31 11:51:09 +0100 | asked a question | SageTeX: sagecommandline problem As a simple example of the problem I have encountered the output looks fine except that the printed matrix $M$ overlaps with the definition of the vector $v.$ Is there a way to add some vertical space below the displayed matrix? |
2019-11-08 23:16:28 +0100 | received badge | ● Necromancer (source) |
2019-11-08 22:21:39 +0100 | answered a question | Solving 3rd degree Diophantine equation in Sage The elliptic curve $E_1: y^2=x^3-x/25+9/125$ is isomorphic to the one $E_2: Y^2=X^3-25X+9\cdot 5^3,$ here we have $X=25x.$ Integral points on $E_1$ are integral points on $E_2.$ The latter can be computed via Sage. Hence the only candidates are $(4/25 : \pm 33/125 : 1)$ on your curve. Therefore there are no integral points. |
2019-10-22 11:42:14 +0100 | commented answer | Elliptic curves - morphism Thank you very much, it work well. |
2019-10-22 10:04:13 +0100 | asked a question | Elliptic curves - morphism Consider the example from the documentation: how to obtain the morphism in this case? |
2018-12-25 12:23:45 +0100 | received badge | ● Nice Answer (source) |
2018-01-04 21:51:09 +0100 | commented question | Changes of variable from quartic to Weierstrass Just a tiny modification of the above code: it yields: |
2017-01-25 15:33:28 +0100 | commented answer | points on elliptic curve Thanks @nbruin for the correction, now using the second suggested test we may go as the result is simply []. |
2017-01-24 22:05:56 +0100 | answered a question | points on elliptic curve I guess the second point Q is given by [-57,216]. I use it in what follows. The result is: e.g. 2P=(339 : 6156 : 1) and 2Q=(339 : -6156 : 1). |
2017-01-04 19:30:45 +0100 | answered a question | FunctionField with more than 1 variable Thank you for the workaround, it helps to compute what I need. There is a small gap at the end, I need to define a polynomial ring over the function field and factor certain polynomials over it. The error message is that it is not implemeted, but I know some factors and I could reduce the problem to a quadratic polynomial. |
2017-01-04 15:41:55 +0100 | asked a question | FunctionField with more than 1 variable I have tried the following to construct an appropriate function field: as a result I got after that I looked for the documentation but only find one variable examples. I also tried a few more versions like but did not work. Thank for any advice in this direction in advance. |
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2016-11-27 19:05:54 +0100 | answered a question | How to get latex expression in exponential notation? The following may help: it gives what you need J K^{-1}. |
2016-11-27 12:30:33 +0100 | marked best answer | Strange output using qsub I wrote a Sage code and it works fine on my notebook: nohup < QE.sage > QE.txt & the output file QE.txt looks OK. When I try to use the same code on a cluster using qsub -q test.q QE.sh then the output is here QE.sh is as follows Also if I use @parallel() on my notebook, then it works as expected: The CPU time is about 2 sec on my notebook using 2 cores on the cluster using less than 12 cores it prints the first pair and that is it after running (not waiting in the que) more than 2 hours. My questions are:
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2016-11-27 12:23:33 +0100 | answered a question | Constant coefficient of Laurent Polynomials You may try the following: It gives a6 as you expect and e.g. is equal to a4. Also you can determine the coefficient of any monomial: is 1. |
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2016-11-19 23:15:54 +0100 | answered a question | General power of a matrix? In many cases the following works: Here one obtains An as follows: It does not work if the given matrix is not similar to a diagonal matrix. |
2016-11-03 17:59:49 +0100 | commented answer | point addition on elliptic curve In fact I just picked up some points to demonstrate point addition over this domain. As I see now your point Q is given, it is not a general point (X,Y) so I am not sure if you really need this FunctionField stuff. Anyway, you can combine @slelievre code with mine: that provides and 2*P+Q is a nice point (more) |
2016-11-02 20:58:08 +0100 | answered a question | point addition on elliptic curve Something that may help: Here the answer is as follows: and |
2016-10-29 00:15:35 +0100 | answered a question | Elliptic curve defined with parameter You may try the following there are many functions to be applied for your curve E: SageMath Doc. Define a point e.g. and compute the double point: To determine some more "small" points on your curve: which provides: |
2016-10-27 18:53:47 +0100 | commented answer | programming of looping to print selected value of m Is not x=(121043P-2*P)[0]? |
2016-10-27 14:23:50 +0100 | answered a question | Polynomial ring modulus integer to univariate polynomial ring over the Integers Your code is almost there, probably you need the following: Here you obtain |
2016-10-27 14:14:36 +0100 | answered a question | programming of looping to print selected value of m You may try something like but when m=3 you have and D=W[0] will not be defined. The same happens for m=5 also and for many other values I would guess. |